DT
May 4, 2026
What are harmonic functions and how do I solve the Dirichlet problem on a disk?
I am studying complex analysis / PDEs and I need to understand harmonic functions. A function is harmonic if it satisfies Laplace's equation:
or in polar coordinates: .
My questions:
- What is the physical significance of harmonic functions (steady-state heat, electrostatics, fluid flow)?
- How does the mean value property characterise harmonic functions?
- How do I solve the Dirichlet problem: find harmonic in the unit disk with boundary condition ?
- What is Poisson's integral formula?
- How are harmonic functions related to analytic functions?
I want to see the solution for on the unit disk.
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1 Answer
DC
Dr. Carlos MendezMay 5, 2026 Accepted**Physical Significance:**
- **Steady-state heat:** Temperature distribution in a region with fixed boundary temperatures
- **Electrostatics:** Electric potential in a charge-free region
- **Fluid flow:** Velocity potential for incompressible, irrotational flow
**Mean Value Property:** If $u$ is harmonic in a domain, then for any disk $B_r(z_0)$:
$$u(z_0) = \frac{1}{2\pi} \int_0^{2\pi} u(z_0 + re^{i\theta}) \, d\theta$$
The value at the center equals the average over the boundary. This characterises harmonic functions (converse also holds).
**Connection to Analytic Functions:**
If $f(z) = u(x, y) + iv(x, y)$ is analytic, then both $u$ and $v$ are harmonic. Every harmonic function is the real part of some analytic function (locally). Given $u$, we can find $v$ via the Cauchy-Riemann equations.
**Poisson's Integral Formula for the Unit Disk:**
The solution to the Dirichlet problem on the unit disk is:
$$u(r, \theta) = \frac{1}{2\pi} \int_0^{2\pi} \frac{1 - r^2}{1 - 2r\cos(\theta - \phi) + r^2} \, f(\phi) \, d\phi$$
**Example: $f(\theta) = \sin^2 \theta$ on the unit disk.**
Using $\sin^2 \theta = \frac{1 - \cos 2\theta}{2}$, the solution is:
$$u(r, \theta) = \frac{1}{2} - \frac{r^2}{2} \cos 2\theta$$
This can be verified to satisfy Laplace's equation and the boundary condition (when $r = 1$: $u(1, \theta) = \frac12 - \frac12 \cos 2\theta = \sin^2 \theta$).
**Separation of variables approach:**
Assume $u(r, \theta) = R(r)\Theta(\theta)$, solve the resulting ODEs, and use Fourier series to match the boundary condition. This gives:
$$u(r, \theta) = \frac{a_0}{2} + \sum_{n=1}^{\infty} r^n (a_n \cos n\theta + b_n \sin n\theta)$$
where $a_n, b_n$ are the Fourier coefficients of $f(\theta)$.
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