MethodMath
Sarah Mitchell
May 22, 2026

How to memorize trigonometric identities without rote memorization learn the connections

I have a trig final next week and Im drowning in identities.

Theres like 50 of them:

  • Pythagorean identities
  • Angle addition formulas
  • Double angle formulas
  • Half angle formulas
  • Sum-to-product
  • Product-to-sum
  • Power-reducing formulas

I cant memorize all of these! Is there a way to learn them by understanding the connections?

I know that most of them come from:

cos(A+B)=cosAcosBsinAsinB\cos(A+B) = \cos A \cos B - \sin A \sin B
sin(A+B)=sinAcosB+cosAsinB\sin(A+B) = \sin A \cos B + \cos A \sin B

And using A=BA = B gives double angle formulas. Using cos2A+sin2A=1\cos^2 A + \sin^2 A = 1 gives the other Pythagorean forms.

But the sum-to-product formulas are still hard. And the half-angle formulas with the ±\pm signs confuse me.

Also: is it true that Euler formula eiθ=cosθ+isinθe^{i\theta} = \cos\theta + i\sin\theta can generate ALL trig identities automatically? How would that work?

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1 Answer

Prof. Chen Wei
Prof. Chen WeiMay 22, 2026 Accepted
Heres a systematic approach that reduces memorization to just THREE core identities: **Core identities (memorize these):** 1. $\sin^2 \theta + \cos^2 \theta = 1$ 2. $\sin(A+B) = \sin A \cos B + \cos A \sin B$ 3. $\cos(A+B) = \cos A \cos B - \sin A \sin B$ **Everything else comes from these:** **Double angle:** Set $B = A$: $$\sin 2A = 2 \sin A \cos A$$ $$\cos 2A = \cos^2 A - \sin^2 A = 2\cos^2 A - 1 = 1 - 2\sin^2 A$$ **Half angle:** Solve $\cos 2\theta = 1 - 2\sin^2 \theta$ for $\sin\theta$: $$\sin \frac{\theta}{2} = \pm \sqrt{\frac{1 - \cos \theta}{2}}$$ **Using Eulers formula** ($e^{i\theta} = \cos\theta + i\sin\theta$) is the most elegant approach: $$e^{i(A+B)} = e^{iA}e^{iB}$$ $$\cos(A+B) + i\sin(A+B) = (\cos A + i\sin A)(\cos B + i\sin B)$$ Multiply out and equate real/imaginary parts — you get both addition formulas instantly! **For product-to-sum:** Use the addition formulas with $P = (A+B)/2$ and $Q = (A-B)/2$. The $\pm$ signs in half-angle formulas are determined by which quadrant $\theta/2$ lies in. On a unit circle, you can derive this visually.

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