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Mike Johnson
Mike Johnson
May 3, 2026

Can you really multiply any two-digit numbers in seconds with this trick?

This trick is all over Instagram:

To multiply 23×4723 \times 4723×47:

20×40=80020 \times 40 = 80020×40=800
20×7=14020 \times 7 = 14020×7=140
3×40=1203 \times 40 = 1203×40=120
3×7=213 \times 7 = 213×7=21

Total: 800+140+120+21=1081800 + 140 + 120 + 21 = 1081800+140+120+21=1081

But isnt this just FOIL? (20+3)(40+7)(20+3)(40+7)(20+3)(40+7) expanded? So its not really a "trick" but just basic algebra?

I showed this to my friend and she was amazed but I was like "thats just the distributive property."

Actually theres another trick: to square a number ending in 5 like 75275^2752:

7×8=567 \times 8 = 567×8=56

Append 25: 562556255625

This one actually IS surprising. Why does this work? Prove it with algebra.

1 answers1.1k views

1 Answer

0
Emily Thompson
May 4, 2026
Accepted
Most two-digit multiplication tricks are place value in disguise. If the numbers are $$(10a+b)(10c+d),$$ then expanding gives $$100ac+10ad+10bc+bd=100ac+10(ad+bc)+bd.$$ For $23\cdot47$, the hundreds contribution is $2\cdot4$, the cross contribution is $2\cdot7+3\cdot4$, and the ones contribution is $3\cdot7$. Handling the carries reconstructs the ordinary product. It is the distributive property, not a separate rule. The shortcut for squaring a number that ends in $5$ follows from the same algebra. Write the number as $10a+5$: $$(10a+5)^2=100a^2+100a+25=100a(a+1)+25.$$ Therefore, multiply the part before the final $5$ by the next integer, then append $25$. For $75^2$, use $a=7$: $$7\cdot8=56,$$ so $$75^2=5625.$$
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