Does the infinite series 9 divided by 10 to the power of n starting from 1 converge to 1 proof
For the question, I want to see a rigorous proof using infinite series.
The decimal can be written as:
This is a geometric series with and .
The sum is .
But someone told me this only works for "convergent" series. What does that mean? And isnt there a number between 0.999... and 1? By the density of real numbers, shouldnt there be?
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For limits, I would first classify the expression before applying any rule.
If direct substitution gives a number, you are done. If it gives $0/0$ or $\infty/\infty$, then algebra, series expansion, or L'Hopital's rule may be useful. If it gives something like $0\cdot\infty$ or $\infty-\infty$, rewrite it into a quotient first.
For example, near $0$ the expansion
$$\sin x=x-\frac{x^3}{6}+O(x^5)$$
often gives the cleanest answer. It also explains why repeated L'Hopital works in some cases but can hide the structure of the expression.
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Dr. Aisha MohammedMay 23, 2026
This helped. The check at the end is the part I usually forget.
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