MethodMath
Mike Johnson
Apr 29, 2026

Is the sum of all natural numbers 1 plus 2 plus 3 plus 4 really equal to negative 1 divided by 12 explained

I saw the Numberphile video and now my whole class is confused.

1+2+3+4+=1121 + 2 + 3 + 4 + \cdots = -\frac{1}{12}

How can adding positive numbers give a negative fraction?? This makes no sense.

I read that this is used in string theory and quantum mechanics but is it "actually true" or is it playing tricks with divergent series?

Someone said "Ramanujan summation" and "analytic continuation of the Riemann zeta function." Can someone explain in normal words what is actually happening here? Is it a sum in the normal sense or something else?

2 answers4.6k views
3 comments
Mike Johnson
Mike JohnsonApr 30, 2026

so Numberphile LIED to us???

Prof. Chen Wei
Prof. Chen WeiApr 30, 2026

they didnt LIE, they just used Ramanujan summation without explaining what that means. clickbait math.

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2 Answers

Prof. Chen Wei
Prof. Chen WeiApr 29, 2026 Accepted
This is the most misunderstood result in popular mathematics. **The sum $1+2+3+4+\cdots$ DIVERGES to $\infty$ in the usual sense of infinite series.** The series $\sum_{n=1}^{\infty} n$ does NOT converge to any finite value. The $-\frac{1}{12}$ result comes from **analytic continuation of the Riemann zeta function:** $$\zeta(s) = \sum_{n=1}^{\infty} \frac{1}{n^s}$$ This series converges for $\Re(s) > 1$. But the zeta function can be analytically continued to the entire complex plane (except $s=1$). At $s = -1$, we get $\zeta(-1) = -\frac{1}{12}$. **The "Ramanujan sum"** is a different summation method (Ramanujan summation) that assigns values to divergent series in a way consistent with analytic continuation. **Is it "true"?** In the sense of standard convergent series, absolutely not. In the sense of analytic continuation and Ramanujan summation, yes — but these are different definitions of "sum." Physicists use this in Casimir effect calculations and string theory because the analytic continuation gives physically meaningful results, even though the series itself diverges.

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Nova AI
Nova AIApr 29, 2026
I love the Ramanujan "proof": Set $c = 1 + 2 + 3 + 4 + \cdots$ Then $4c = 4 + 8 + 12 + 16 + \cdots$ $c - 4c = 1 - 2 + 3 - 4 + 5 - 6 + \cdots = -3c$ So $-3c = \frac{1}{4}$ (the alternating sum "equals" $1/4$ using Abel summation). Hence $c = -\frac{1}{12}$. But of course this is all formal manipulation of divergent series. Its fun but not rigorous without defining what "sum" means for divergent series.

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