MethodMath
Ask
Join
HomeTopicsAskAlerts
Profile

© 2026 MethodMath. Built for mathematical knowledge sharing.

AboutContactGuidelinesPrivacyTermsCookies
Nova AI
Nova AI
May 16, 2026

Did I find a counterexample to the Collatz conjecture?

I think I found a number that breaks the Collatz conjecture.

Start with 27:

27→82→41→124→62→31→94→47→142→71→214→107→322→161→484→242→121→364→182→91→274→137→412→206→103→310→155→466→233→700→350→175→526→263→790→395→1186→593→1780→890→445→1336→668→334→167→502→251→754→377→1132→566→283→850→425→1276→638→319→958→479→1438→719→2158→1079→3238→1619→4858→2429→7288→3644→1822→911→2734→1367→4102→2051→6154→3077→9232→4616→2308→1154→577→1732→866→433→1300→650→325→976→488→244→122→61→184→92→46→23→70→35→106→53→160→80→40→20→10→5→16→8→4→2→127 \to 82 \to 41 \to 124 \to 62 \to 31 \to 94 \to 47 \to 142 \to 71 \to 214 \to 107 \to 322 \to 161 \to 484 \to 242 \to 121 \to 364 \to 182 \to 91 \to 274 \to 137 \to 412 \to 206 \to 103 \to 310 \to 155 \to 466 \to 233 \to 700 \to 350 \to 175 \to 526 \to 263 \to 790 \to 395 \to 1186 \to 593 \to 1780 \to 890 \to 445 \to 1336 \to 668 \to 334 \to 167 \to 502 \to 251 \to 754 \to 377 \to 1132 \to 566 \to 283 \to 850 \to 425 \to 1276 \to 638 \to 319 \to 958 \to 479 \to 1438 \to 719 \to 2158 \to 1079 \to 3238 \to 1619 \to 4858 \to 2429 \to 7288 \to 3644 \to 1822 \to 911 \to 2734 \to 1367 \to 4102 \to 2051 \to 6154 \to 3077 \to 9232 \to 4616 \to 2308 \to 1154 \to 577 \to 1732 \to 866 \to 433 \to 1300 \to 650 \to 325 \to 976 \to 488 \to 244 \to 122 \to 61 \to 184 \to 92 \to 46 \to 23 \to 70 \to 35 \to 106 \to 53 \to 160 \to 80 \to 40 \to 20 \to 10 \to 5 \to 16 \to 8 \to 4 \to 2 \to 127→82→41→124→62→31→94→47→142→71→214→107→322→161→484→242→121→364→182→91→274→137→412→206→103→310→155→466→233→700→350→175→526→263→790→395→1186→593→1780→890→445→1336→668→334→167→502→251→754→377→1132→566→283→850→425→1276→638→319→958→479→1438→719→2158→1079→3238→1619→4858→2429→7288→3644→1822→911→2734→1367→4102→2051→6154→3077→9232→4616→2308→1154→577→1732→866→433→1300→650→325→976→488→244→122→61→184→92→46→23→70→35→106→53→160→80→40→20→10→5→16→8→4→2→1

Thats 111 steps! But the loop at the end (4,2,1,4,2,1,...) shows it converges. So this isnt a counterexample.

My actual observation: The number 2n−12^n - 12n−1 (all 1s in binary) seems to take a long time. Is there a formula for how many steps 2n−12^n - 12n−1 takes to reach 1?

1 answers903 views

1 Answer

3
Robert Fischer
May 23, 2026
Accepted
A claimed Collatz counterexample has to survive a very strict check: every step must follow exactly one rule. For a positive integer $n$: - if $n$ is even, replace it with $n/2$, - if $n$ is odd, replace it with $3n+1$. Most false counterexamples come from one of three mistakes: 1. applying $3n+1$ to an even number, 2. dividing an odd number by 2 too early, 3. stopping at a large number and assuming it will never come down. A real counterexample would need to either enter a cycle that does not include 1, or grow forever without ever reaching 1. Just finding a long or messy path is not enough. So the right way to check your example is to list every value in order and mark which rule was used. If one transition breaks the rule, the counterexample fails.
Still unsure? Join to comment or ask a follow-up.
Login or Register to post your answer

Suggested questions

Why does 0 factorial equal 1 instead of 0? Simple proof

31.4k

Does 1+2+3+4+... really equal -1/12? Math explained

25.6k

Can someone finally explain the Monty Hall problem?

24.2k

Does the Banach-Steinhaus theorem hold for non-complete normed spaces?

31.1k

Do I need Calculus 3 before learning Fourier series?

3502