Question details
Why is the integral of 1/x equal to the natural logarithm of x?
I know that: ∫ 1/x dx = ln|x| + C But what is the deeper reason for this? Is it because the derivative of ln x is 1/x, or is there a more fundamental definition? How would you derive this result from first principles without relying on the derivative of the exponential function? Also, why does this only work for x^(-1) and not for other powers like x^(-2)?
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